# Function arrow::compute::lexicographical_partition_ranges

```
pub fn lexicographical_partition_ranges(
columns: &[SortColumn]
) -> Result<impl Iterator<Item = Range<usize>>, ArrowError>
```

ðŸ‘ŽDeprecated: Use partition

## Expand description

Use `partition`

instead. Given a list of already sorted columns, find
partition ranges that would partition lexicographically equal values across
columns.

The returned vec would be of size k where k is cardinality of the sorted values; Consecutive values will be connected: (a, b) and (b, c), where start = 0 and end = n for the first and last range.